"Draw the Lewis Dot Structure for BH^−2. What is the electron geometry? What is the molecular geometry?"
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Answer

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Step 1:
: Draw the Lewis structure for BH${}^{- 2}$.

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First, let's distribute the negative 2 charge to the hydrogen atoms, since boron cannot have a formal charge of + 1. This gives us three B-H bonds and two additional negative charges on two hydrogen atoms.

Step 2:
: Determine the total number of valence electrons.

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Boron has 3 valence electrons, and each hydrogen atom has 1 valence electron. In addition, there are 2 extra electrons from the charge. Therefore, the total number of valence electrons is:

Step 3:
: Place the electrons around the atoms using Lewis dot structure rules.

Final Answer

The Lewis structure for BH${}^{- 2}$ is: B : H : H : H : H : H : : : : : : : : : : : : : : The electron geometry is trigonal bipyramidal, and the molecular geometry is trigonal planar.