Answer
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Step 1:I'm sorry for the inconvenience caused by the missing file content.
Problem: Solve the quadratic equation $$x^{2}-5x+6 = 0$$.
In order to provide a solution, I need to know the problem. However, I will give you an example of how I would structure my solution for a hypothetical algebra problem.
Step 2:: Identify the coefficients a, b, and c.
In this equation, $$a=1$$, $$b=-5$$, and $$c=6$$.
Step 3:: Plug in the values of a, b, and c into the quadratic formula.
The quadratic formula is: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Step 4:: Calculate the value under the square root, which is b^2 - 4ac.
(-5)^{2} - 4*1*6 = 25 - 24 = 1
Step 5:: Calculate the two possible solutions for x by substituting the value of the square root into the quadratic formula.
x = \frac{-(-5) - \sqrt{1}}{2*1} = \frac{5 - 1}{2} = \frac{4}{2} = 2
For the positive square root: For the negative square root:
Final Answer
x = 3.
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