QQuestionChemistry
QuestionChemistry
Draw the Lewis structure for SiH^4. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Include all hydrogen atoms. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom.
Draw the Lewis structure for CO. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.
Draw the Lewis structure for SF^2. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom.
Draw the Lewis structure for H^2SO^4 (H is bonded to O). Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Include all hydrogen atoms. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom.
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Answer
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Step 1:: Draw the Lewis structure for SiH^4.
Silane (SiH4) has a total of 4 valence electrons from Silicon and 1 valence electron from each Hydrogen atom. To start, place Silicon (Si) in the center and surround it with 4 Hydrogen (H) atoms. SiH^4 Lewis structure: Si H H H H
Step 2:: Add the remaining valence electrons to complete the octet for each atom.
Adding the remaining 4 valence electrons: .. Si H : H : H : H : :
Step 3:: Add the remaining electrons to form lone pairs on the Hydrogen atoms.
Since Hydrogen needs only 2 electrons to complete its duplet, there are no lone pairs on the Hydrogen atoms.
Step 4:: Draw the Lewis structure for CO.
Carbon Monoxide (CO) has a total of 4 valence electrons from Carbon and 6 valence electrons (3 lone pairs) from Oxygen. Place Carbon (C) and Oxygen (O) atoms next to each other. CO Lewis structure: C O
Step 5:: Add the remaining valence electrons to complete the octet for each atom.
Adding the remaining 2 valence electrons: C = O
Step 6:: Add the remaining electrons to form lone pairs on the Oxygen atom.
Adding the remaining 4 electrons to form 2 lone pairs on the Oxygen atom: C = O: :
Step 7:: Draw the Lewis structure for SF^2.
Sulfur Difluoride (SF2) has a total of 6 valence electrons from Sulfur and 7 valence electrons (3 lone pairs) from each Fluorine atom. Place Sulfur (S) in the center and surround it with 2 Fluorine (F) atoms. SF^2 Lewis structure: S F F
Step 8:: Add the remaining valence electrons to complete the octet for each atom.
Adding the remaining 2 valence electrons: S - F F
Step 9:: Add the remaining electrons to form lone pairs on the Fluorine atoms.
Adding the remaining 4 electrons to form 2 lone pairs on each Fluorine atom: S - F : : F : :
Step 10:: Draw the Lewis structure for H^2SO^4 (H is bonded to O).
Sulfuric Acid (H^2SO4) has a total of 16 valence electrons from Sulfur, 8 valence electrons (4 lone pairs) from Oxygen atoms, and 1 valence electron from each Hydrogen atom. Place Sulfur (S) in the center and surround it with 4 Oxygen (O) atoms and 2 Hydrogen (H) atoms. H^2SO^4 Lewis structure: H H S O O O H
Step 11:: Add the remaining valence electrons to complete the octet for each atom.
Adding the remaining 4 valence electrons: H - S - O : O : O - H
Step 12:: Add the remaining electrons to form lone pairs on the Oxygen atoms.
Adding the remaining 4 electrons to form 2 lone pairs on each Oxygen atom: H - S - O : O : O - H : : : :
Final Answer
The Lewis structures for SiH^4, CO, SF^2, and H^2SO^4 are shown above. Remember to follow the steps to create each structure, including adding all valence electrons, forming bonds, and adding lone pairs.
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