Draw two Lewis structures for a compound with the formula C4H10. No atom bears a charge, and all carbon ato...

Question

Draw two Lewis structures for a compound with the formula C4H10. No atom bears a charge, and all carbon atoms have complete octets.

CramX · Accepted Answer

Step 1: I'll solve this Lewis structure problem step by step:. Step 2: : Determine the total number of valence electrons. - Carbon (C) has 4 valence electrons - Hydrogen (H) has 1 valence electron Step 3: : Identify possible carbon skeleton arrangements. - C4H10 can have two possible structural isomers: Step 4: . Straight-chain (n-butane) Step 5: . Branched-chain (isobutane) Step 6: : Draw Lewis structure for n-butane. - Connect carbons in a linear chain - Attach hydrogens to fill octets - Distribute 26 valence electrons H-C-C-C-C-H \ | | | | \ H H H H \end{array}$ Step 7: : Draw Lewis structure for isobutane. - Create a branched carbon skeleton - Attach hydrogens to fill octets - Distribute 26 valence electrons \quad H \ \quad | \ H-C-C-C-H \ \quad | \quad | \ \quad H \quad H \end{array}$ Final Answer: Two valid Lewis structures for C4H10 are n-butane and isobutane, each satisfying the requirements of no charged atoms and complete octets for carbon atoms.

Q
QuestionChemistry

Answer

Full Solution Locked

Step 1:
I'll solve this Lewis structure problem step by step:

Step 2:
: Determine the total number of valence electrons

Step 3:
: Identify possible carbon skeleton arrangements

Final Answer

Need Help with Homework?

Related Questions

Company

Explore

Study Tools

QQuestionChemistry

AnswerHelpful