QQuestionChemistry
QuestionChemistry
Match the following compounds to their likely solubility in water: C^2H^5OH, I^2, KF with least, middle, most. Could you explain it as well?
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Answer
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Step 1:Sure, I'd be happy to help you with that!
When predicting the solubility of a compound in water, we can use the following general rules:
Step 2:
Ionic compounds tend to be soluble in water.
Step 3:
Polar covalent compounds with polar bonds tend to be soluble in water.
Step 4:
Nonpolar covalent compounds tend to be insoluble in water. Let's apply these rules to the given compounds:
Step 5:
C^2H^5OH: This is ethanol, a polar covalent compound with a polar bond between carbon and oxygen. It is capable of forming hydrogen bonds with water molecules, so it is soluble in water.
Step 6:
I^2: This is iodine, a nonpolar covalent compound. It is not capable of forming hydrogen bonds with water molecules, so it is insoluble in water.
Step 7:
KF: This is potassium fluoride, an ionic compound. Ionic compounds are generally soluble in water, so KF is soluble in water. So, the solubility of the given compounds in water from least to most is: I^2, C^2H^5OH, KF.
Final Answer
* I^2: insoluble * C^2H^5OH: soluble * KF: soluble
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