QQuestionAnatomy and Physiology
QuestionAnatomy and Physiology
The specific heat of water is 4.184 J/goC. How many Joules of heat energy would be required to raise the temperature of 157.0g of water from 32.7oC to 50.0oC?
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Answer
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Step 1:: Write down the formula for heat transfer, which is given by the equation Q = mc\Delta T, where:
- $$\Delta T$$ is the change in temperature
- m is the mass of the substance
Step 2:: Plug in the values given in the problem.
Q = (157.0 g)(4.184 \frac{J}{g^oC})(17.3^oC)
Step 3:: Perform the multiplication.
Q = (157.0)(4.184)(17.3)
Step 4:: Calculate the result.
Q = 12154.464 J
Final Answer
Approximately 12154.46 Joules of heat energy would be required to raise the temperature of 157.0 g of water from 32.7^oC to 50.0^oC.
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