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What is the formula for finding the base of a triangle?
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Answer

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Step 1
: Recall that the formula for finding the base of a triangle is given when at least one side length and one angle measure are known.

b = a \sin(\theta)
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+P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAWnRSTlMAMnT^0 /wD+oDv^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAXklEQVR^4Ae^3U^6Q^3AIAwF^0Jbb/Ri^6UK^5k^5rHzKC^9 + 8wcKykrq^6u^7s^7Ly/ 39 /r^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAWnRSTlMAMnT^0 /wD+oDv^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAXklEQVR^4Ae^3U^6Q^3AIAwF^0Jbb/Ri^6UK^5k^5rHzKC^9 + 8wcKykrq^6u^7s^7Ly/ 39 /r^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAWnRSTlMAMnT^0 /wD+oDv^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAXklEQVR^4Ae^3U^6Q^3AIAwF^0Jbb/Ri^6UK^5k^5rHzKC^9 + 8wcKykrq^6u^7s^7Ly/ 39 /r^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAWnRSTlMAMnT^0 /wD+oDv^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAXklEQVR^4Ae^3U^6Q^3AIAwF^0Jbb/Ri^6UK^5k^5rHzKC^9 + 8wcKykrq^6u^7s^7Ly/ 39 /r^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAWnRSTlMAMnT^0 /wD+oDv^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAXklEQVR^4Ae^3U^6Q^3AIAwF^0Jbb/Ri^6UK^5k^5rHzKC^9 + 8wcKykrq^6u^7s^7Ly/ 39 /r^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAWnRSTlMAMnT^0 /wD+oDv^6 +vj^4 +P^09PT^29vb^09fX^18fHy^8vL^29vb^29vZ^7VDrhAAAAXklEQVR^4Ae^3U^6Q^3AIAwF^0Jbb/Ri^6

Final Answer

b = a \sin(\theta)

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