Answer
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Step 1:: Determine the total number of valence electrons in the Lewis structure for H^3PO^4.
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Phosphorus (P) is in the 5th period and group VA of the periodic table, so it has 5 valence electrons. Each hydrogen (H) atom has 1 valence electron. Therefore, the total number of valence electrons in H^3PO^4 is:
Step 2:: Draw the skeletal structure of H^3PO^4.
Phosphorus is the central atom, and four sites are occupied by hydrogen atoms or single bonds. The skeletal structure is: ``` H - P - O | H | H ```
Step 3:: Place the remaining valence electrons on the outer atoms as lone pairs.
Since there are 8 valence electrons, and 8 electrons are already in the skeletal structure, there are no more electrons to place.
Final Answer
The closest correct option is D'), which includes the double-bonded oxygen atom with two lone pairs of electrons.
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