QQuestionChemistry
QuestionChemistry
Write a balanced chemical equation for the standard formation reaction of liquid acetic acid, CH^3COOH.
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Answer
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Step 1:: Understand the problem
The question asks us to write a balanced chemical equation for the standard formation reaction of liquid acetic acid (CH^3COOH). Standard formation reactions are reactions where one mole of a compound is formed from its elements in their standard states.
Step 2:: Write the unbalanced chemical equation
\text{C (s)} + \text{O}_2 \text{ (g)} + \text{H}_2 \text{ (g)} \rightleftharpoons \text{CH}_3\text{COOH (l)}
We start by writing the unbalanced chemical equation for the formation of acetic acid from its elements in their standard states.
Step 3:: Balance the chemical equation
\text{C (s)} + \text{O}_2 \text{ (g)} + \text{2H}_2 \text{ (g)} \rightleftharpoons \text{CH}_3\text{COOH (l)}
To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides. In this case, we can balance the equation by adding coefficients in front of the reactants and products.
Step 4:: Check the balancing
Now, let's check if the equation is balanced. There are: - 1 carbon atom on both sides - 2 oxygen atoms on the left side and 2 oxygen atoms on the right side - 2 hydrogen atoms on the left side and 2 hydrogen atoms on the right side Since the number of atoms of each element is the same on both sides, the equation is balanced.
Final Answer
The balanced chemical equation for the standard formation reaction of liquid acetic acid is: \text{C (s)} + \text{O}_2 \text{ (g)} + \text{2H}_2 \text{ (g)} \rightleftharpoons \text{CH}_3\text{COOH (l)}
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