BTM8106-8-2 Jackson Even-Numbered Chapter Exercises
Even-numbered exercises analyzing business research techniques.
Benjamin White
Contributor
4.7
34
7 months ago
Preview (3 of 9 Pages)
100%
Purchase to unlock
Page 1
Loading page ...
BTM8106-8-21Part IBTM8106-8-2JACKSON EVEN-NUMBERED CHAPTER EXERCISES (PP. 220-221).2a.Thisisa one-tail test because themanufacturers of the toothpastewant toprovethattheirnew toothpaste prevents more cavitiesthan other brands of toothpaste(their sample vs. thegeneral population.2b.Ho: μcavities withtoothpaste1≤μcavities in general populationHa:μcavities with toothpaste1>μ cavities in generalpopulation2c.σx̅=1.12 /√60 = 1.12 / 7.745: =.144z= 1.73-1.5 /.144= .23/.144: =1.5972d.±1.645(Jackson, p.205).2e.No, it should not be rejected. If the p-value is large,(> .05)than the evidence against the nullhypothesis is small.The conclusion is that using the manufacturer’s toothpaste prevents morecavities than their competitor’s toothpaste.2f.σx̅= 1.12 /√60 = 1.12 / 7.745: = .144CI = 1.50±1.96 x 1.12 /√60: = 1.50±1.96 x .144: = 1.50±.28341.5-.2834 =1.2166, 1.5 + .2834 =1.78344.He is morelikely to make a Type I error.6a.This is a two-tailed test.6b.Ho: μclassical music listeners≤μspatial abilityin general populationHa: μclassical musiclisteners> μspatial ability ingeneral population6c.x̅= 52 +59 + 63 + 65 + 58 + 55 + 62 + 63 + 53 + 59 + 57 + 61 + 60 + 59 / 14: = 59(52-59)² / 14-1, + (59-59)² / 14–1: = 3.80259-58 / 3.802 /√14 = 1 / 1.0161:.9841
Page 2
Page 3
Preview Mode
This document has 9 pages. Sign in to access the full document!