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BTM8107-8 Week: 4 Analyze t Test and ANOVA Correct Answers

Solutions for t-tests and ANOVA statistical analysis.

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BTM8107-8 Week: 4 Analyze tTest and ANOVACorrectAnswersPart A. Dependent t testFor this assignment, we are interested in finding out whether participation in a creativewriting course results in increased scores of a creativity assessment. Forthis part of theactivity, you will be using the data file “Activity 4a.sav”. In this file, “Participant” is thenumeric student identifier, “CreativityPre” contains creativity pre-test scores, and“CreativityPost” contains creativity post-test scores. A total of 40 students completed thepre-test, took the creativity course, and then took the post-test.Answer:Here the null hypothesis H0: the participation in a creative writing course results is notincreased in scores of creative assessment against the alternative H1: the participation ina creative writing course results is increased in scores of creative assessment. In otherwords we can say the null hypothesis H0: d=0 against the alternative hypothesis H1: d>0where d is mean of the sample differences of the two sample.This is a paired sample t test. And the test statistics ist =Σ(differences of the observation)/√((NΣ(differences of observation)2-(Σ(differencesof observation))2)/ (N-1)). Where N is the sample size, here N=40.The SPSS result:Paired Samples StatisticsMeanNStd. DeviationStd. Error MeanPair 1Creativity pre-test40.15408.3041.313Creativity post-test43.35409.5981.518The means of Creativity pre-test is 40.15, standard deviation is 8.304 and the mean ofCreativity post-test is 43.35 and standard deviation is 9.598.Paired Samples CorrelationsNCorrelationSig.Pair 1Creativity pre-test &Creativity post-test40.650.000

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Document Details

University
Northcentral University
Course
BTM 8107 8
Subject
Statistics

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