Engineering Mechanics: Dynamics 14th Edition Solution Manual

Find all the textbook answers you need with Engineering Mechanics: Dynamics 14th Edition Solution Manual, featuring clear, step-by-step solutions.

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1Solutiona=2t-6dv=adtLv0dv=Lt0(2t-6) dtv=t2-6tds=vdtLs0ds=Lt0(t2-6t) dts=t33-3t2Whent=6s,v=0Ans.Whent=11s,s=80.7 mAns.12–1.Starting from rest, a particle moving in a straight line has anacceleration ofa=(2t-6) m>s2, wheretis in seconds. Whatis the particle’s velocity whent=6 s, and what is its positionwhent=11 s?Ans:s=80.7 m

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