Momentum, Kinetic Energy, And Vector Analysis In Physics Problems

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Momentum, Kinetic Energy, and Vector Analysis in Physics ProblemsFor problem #5:I don’t understand why it says these are incorrect.This is most certainly a conservation of momentum problem.The momentum before the string is burned is zero, so themomentum after the string is burnedmust also be zero.(m + 3m)*0 = 3m(2.80) + m(v)0 = 8.40 + vv =-8.40 m/sperhaps you need to put it in as-8.40 for three significant figures? This is right.The kinetic energy formula is (1/2)mv^2The total kinetic energy is (1/2)(0.5)(-8.40)^2 + (1/2)(3*0.5)(2.80)^2 = 23.5 JAgain I think it may be that it just wants three significant figures. These numbers are right.For problem #6 part a:I used 1.20 instead of 1.25The answer for the first part should be 2.18 kg m/sFor problem #10 part b:Made a stupid mistake here. Moved the decimal the wrong way.The correct answer is 4.26*10-14J

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