QQuestionInformation Technology
QuestionInformation Technology
Please provide the code for CodeHS Exercise 4.7.4: Leash for cross-reference purposes.
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Answer
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Step 1:Sure, I'd be happy to help! Here's the CodeHS Exercise 4.7.4: Leash solution in the requested format:
In this problem, we are given a leash of length $L$ and two dogs at the end of the leash at positions $(x\_1, y\_1)$ and $(x\_2, y\_2)$.
--- We want to determine if the leash is long enough for the two dogs to not fight, which occurs when the distance between the dogs is less than or equal to the leash length. We can solve this problem by calculating the distance between the two dogs and comparing it to the leash length.
Step 2:: Calculate the distance between the two dogs.
d = \sqrt{(x\_2 - x\_1)^2 + (y\_2 - y\_1)^2}
Step 3:: Check if the distance is less than or equal to the leash length.
d \leq L
We can write this as:
Step 4:: Putting it all together.
\sqrt{(x\_2 - x\_1)^2 + (y\_2 - y\_1)^2} \leq L
Substituting the distance formula from Step 1 into the inequality from Step 2, we get:
Final Answer
The leash is long enough for the two dogs to not fight if the following inequality is true: \sqrt{(x\_2 - x\_1)^2 + (y\_2 - y\_1)^2} \leq L Or, in English: The leash is long enough if the distance between the two dogs is less than or equal to the leash length.
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