QQuestionMathematics
QuestionMathematics
Calculate the 68%, 95%, and 99.7% confidence intervals for the sample proportions. Round all answers to the nearest ten-thousandth.
68% CI: _______
95% CI: _______
99.7% CI: _______
Use the Confidence Interval Formula:
p \pm z \sqrt{\frac{p(1 -p)}{n}}
Type your answers in the spaces provided.
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Answer
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Step 1:I'll solve this step by step using the confidence interval formula for proportions.
- Confidence Interval Formula: $$p \pm z \sqrt{\frac{p(1-p)}{n}}
Given: - We need to calculate 68%, 95%, and 99.7% confidence intervals
Step 2:: Identify the z-scores for different confidence levels
- 68% CI: z = 1 - 95% CI: z = 2 - 99.7% CI: z = 3
Step 3:: Plug in the z-values into the confidence interval formula
- 99.7% CI: $$p \pm 3 \sqrt{\frac{p(1-p)}{n}}
- 95% CI: p \pm 2 \sqrt{\frac{p(1 -p)}{n}} Note: Without specific values for p and n, I cannot calculate exact numerical values. The formula shows how to construct the confidence intervals by adding and subtracting the margin of error.
Final Answer
- 68% CI: p \pm 1 \sqrt{\frac{p(1 -p)}{n}} - 95% CI: p \pm 2 \sqrt{\frac{p(1 -p)}{n}} - 99.7% CI: p \pm 3 \sqrt{\frac{p(1 -p)}{n}}
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