QQuestionMathematics
QuestionMathematics
Calculate the class width of this data and construct a frequency distribution for this data set using six classes. Enter the lower and upper class limits of each range in the respective boxes and then fill in the corresponding frequency. Data set: $25,44,23,31,69,60,36,53,54,21,65,36,68,55,53,55,45,52,1$, 48
1. Calculate the class width.
2. Construct the frequency distribution.
| Lower Class Limit | Upper Class Limit | Frequency |
| :-- | :-- | :-- |
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Answer
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Step 1:I'll solve this step by step, following the LaTeX formatting guidelines precisely:
Step 2:: Calculate the Range
- Range = Maximum - Minimum = $$69 - 21 = 48
- First, find the minimum and maximum values in the data set
Step 3:: Determine Class Width
- Class width = $$\frac{\text{Range}}{\text{Number of Classes}} = \frac{48}{6} = 8
- Number of classes specified: 6
Step 4:: Create Class Intervals
- Start with the minimum value ($$21$$)
- Create 6 intervals of width 8 Frequency Distribution:
Step 5:21 - 28
2. $$29 - 36
Step 6:37 - 44
4. $$45 - 52
Step 7:53 - 60
6. $$61 - 68
Step 8:: Count Frequencies
1. $$21 - 28$$: 2 values ($$21, 23$$)
Step 9:29 - 36: 3 values (30, 31, 36, 36)
3. $$37 - 44$$: 2 values ($$44, 45$$)
Step 10:45 - 52: 4 values (48, 52, 53, 53)
5. $$53 - 60$$: 4 values ($$54, 55, 55, 60$$)
Step 11:61 - 68: 4 values (65, 68, 69)
| $$61$$ | $$68$$ | $$3$$ |
Frequency Distribution Table: | Lower Class Limit | Upper Class Limit | Frequency | | :-- | :-- | :-- |
Final Answer
- Class Width: 8 - Frequency Distribution completed as shown in the table above
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