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Find an equation of the tangent line to the graph of y = g(x) at x = 5 if g(5) = - 3 and g'(5) = 6 Enter your answer in terms of y and x.
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Step 1:
: Recall the point-slope form of a linear equation, which is y - y\_1 = m(2$).

Here, m is the slope and (x\_1, y\_1) is a point on the line. In this case, we are given the slope g'(5) = 6 and a point (5, g(2$)) = (5, - 3). We will use this information to find the equation of the tangent line.

Step 2:
: Since the slope of the tangent line is given as g'(5) = 6, we can directly use this value for m in the point-slope form.

Thus, the equation of the tangent line becomes: y - y\_1 = 6(x - x\_1)

Step 3:
: Now, we substitute the point (5, - 3) into the equation:

y - (- 3) = 6(x - 5)

Step 4:
: Simplify the equation:

y = 6x - 30 - 3

Step 5:
: Further simplification:

y = 6x - 33

Final Answer

The equation of the tangent line to the graph of y = g(x) at x = 5 is y = 6x - 33.