Answer
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Step 1:: Identify the base lengths and height of the first trapezoid.
The height is denoted as $h$.
The base lengths are given as 5 cm and 11 cm, and the height is given as 7 cm.
Step 2:: Recall the formula for the area of a trapezoid.
A = \frac{1}{2}h(b_1 + b_2)
Step 3:: Plug in the values for the first trapezoid.
A_1 = \frac{1}{2}(7 \text{ cm})(5 \text{ cm} + 11 \text{ cm})
Step 4:: Calculate the area of the first trapezoid.
A_1 = 56 \text{ cm}^2
Step 5:: Identify the base lengths and height of the second trapezoid.
The height is denoted as $h$.
The base lengths are given as 6 cm and 8 cm, and the height is given as 4 cm.
Step 6:: Calculate the area of the second trapezoid.
A_2 = 28 \text{ cm}^2
Final Answer
The areas of the given trapezoids are 56 cm² and 28 cm² for the first and second trapezoids, respectively.
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