QQuestionMathematics
QuestionMathematics
Find the line's slope and a point on the line.
y + 1 = -\frac{2}{3}(x- 1)
slope: $\square$
point on the line: $\left(\square, \square\right)$
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12 months agoReport content
Answer
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Step 1:I'll solve this step by step, following the LaTeX formatting guidelines precisely:
Step 2:: Rearrange the equation to slope-intercept form
y + 1 = -\frac{2}{3}x + \frac{2}{3}
• Distribute the -\frac{2}{3}:
Step 3:: Solve for y
y = -\frac{2}{3}x - \frac{1}{3}
• Subtract 1 from both sides: • Simplify the constant term:
Step 4:: Identify the slope
• In slope-intercept form $$y = mx + b$$, the coefficient of x is the slope
• Slope = -\frac{2}{3}
Step 5:: Find a point on the line
• Point: $$(1, -1)
• We can use the point (1, y) by substituting x = 1 into the original equation
Final Answer
• Slope: -\frac{2}{3} • Point on the line: (1, - 1)
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