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QuestionMathematics

"If a person can select 3 presents from 10 presents under the tree, how many different combinations are there? A. 120 B. 30 C. 720 D. 10"
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Answer

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Step 1:
Let's solve this step by step using combination principles:

Step 2:
: Identify the Problem Type

This is a combination problem where we need to calculate how many ways we can select 3 presents from a total of 10 presents.

Step 3:
: Recall the Combination Formula

- $$r$$ is the number of items being selected (3 presents)
Where:

Step 4:
: Calculate the Combination

\binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10!}{3!(7)!}

Step 5:
: Expand the Calculation

= \frac{10 \cdot 9 \cdot 8 \cdot 7!}{(3 \cdot 2 \cdot 1) \cdot 7!}

Step 6:
: Simplify

= \frac{10 \cdot 9 \cdot 8}{3 \cdot 2 \cdot 1} = \frac{720}{6} = 120

Final Answer

Key Insight: This means there are 120 unique ways to select 3 presents from 10 presents, where the order of selection doesn't matter.