CramX Logo

Q
QuestionMathematics

Loading...
8 months agoReport content

Answer

Full Solution Locked

Sign in to view the complete step-by-step solution and unlock all study resources.

Step 1:
I will solve the first three problems from Section One.

Step 2:

Which of the following sets are equal?

Step 3:
: Find the solutions for the quadratic equations in set A and B.

So, $x = 2,1$.
Thus, set A = {1, 3}. Thus, set B = {1, 2}.

Step 4:
: Compare the sets found in Step 1.

Set A and set B are not equal since they do not have the same elements. Set A = {1, 3} and set B = {1, 2}.

Step 5:
: Compare the other sets.

Set C = {x | x ∈ ℕ, x < 3} = {1, 2} Set E = {1, 2} Set G = {3, 1} Set H = {1, 1, 3} Set C and set E are equal. Set G and set H are not equal to any other sets.

Final Answer

Set A ≠ Set B, Set A = {1, 3}, Set B = {1, 2}, Set C = Set E = {1, 2}, Set G ≠ {1, 2, 3}, Set H ≠ {1, 2, 3}. 2. List the elements of the following sets if the universal set is U = {a, b, c, ..., y, z}. Step 1: Find the elements of set A. Set A = {x |x is a vowel} So, set A = {a, e, i, o, u}. Step 2: Find the elements of set C. Set C = {x |x precedes f in the alphabet} So, set C = {a, b, c, d, e, g}. Step 3: Find the elements of set B. Set B = {x |x is a letter in the word “little”} So, set B = {l, i, t, t, l, e}. Step 4: Find the elements of set D. Set D = {x |x is a letter in the word “title”} So, set D = {t, i, t, l, e}. Step 5: Compare the sets. Set A ≠ Set C, Set A ≠ Set B, Set A ≠ Set D. Set A = {a, e, i, o, u}, Set C = {a, b, c, d, e, g}, Set B = {l, i, t, t, l, e}, Set D = {t, i, t, l, e}. 3. Let A= {1,2,...,8,9}, B={2,4,6,8}, C={1,3,5,7,9}, D={3,4,5}, E={3,5}. Which of the these sets can equal a set X under each of the following conditions? Step 1: Find the sets that can be equal to a set X under the given conditions. (a) X and B are disjoint. The only set that is disjoint from set B is set C. So, X = C. (c) X⊆A but X ⊈ C. Set D and set E can be equal to a set X under this condition. So, X = D or X = E. (b) X ⊆ D but X ⊈ B. Set E can be equal to a set X under this condition. So, X = E. (d) X⊆C but X ⊈ A. No set can be equal to a set X under this condition because all sets have elements in common with set A. X = C for condition (a), X = D or X = E for condition (c), X = E for condition (b), no set for condition (d).