Q
QuestionMathematics

The Cartesian coordinates of a point are given. (a) (โˆ’6, 6) (i) Find polar coordinates (r, ๐œƒ) of the point, where r > 0 and 0 โ‰ค ๐œƒ < 2๐œ‹. (ii) Find polar coordinates (r, ๐œƒ) of the point, where r < 0 and 0 โ‰ค ๐œƒ < 2๐œ‹. (b) (4, 4) (i)Find polar coordinates (r, ๐œƒ) of the point, where r > 0 and 0 โ‰ค ๐œƒ < 2๐œ‹. (ii) Find polar coordinates (r, ๐œƒ) of the point, where r < 0 and 0 โ‰ค ๐œƒ < 2๐œ‹.
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Answer

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Step 1:

So, the polar coordinates of the point are $(6\sqrt{2}, \frac{7\pi}{4})$.
Substituting these values into the formulas, we get:

Step 2:

So, the polar coordinates of the point are $(-6\sqrt{2}, \frac{15\pi}{4})$.
In this case, we need to add $\pi$ to our value of $\theta$:

Step 3:

Since $0 \leq \theta < 2\pi$, we don't need to add any multiples of $2\pi$ to our result.
Using the same formulas as before, we get:

Step 4:

So, the polar coordinates of the point are $(-4\sqrt{2}, \frac{5\pi}{4})$.
In this case, we need to add $\pi$ to our value of $\theta$:

Final Answer

(a) (i) $(6\sqrt{2}, \frac{7\pi}{4})$ (a) (ii) $(- 6\sqrt{2}, \frac{15\pi}{4})$ (b) (i) $(4\sqrt{2}, \frac{\pi}{4})$ (b) (ii) $(- 4\sqrt{2}, \frac{5\pi}{4})$