QQuestionMathematics
QuestionMathematics
What is the volume of the box?
\frac{1}{4} \, \text{ft}
- \times
4 \frac{1}{2} \, \text{ft}^3
72 \, \text{ft}^3
1 \frac{1}{8} \, \text{ft}^3
18 \, \text{ft}^3
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Answer
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Step 1:I'll solve this step-by-step using the volume calculation method and proper LaTeX formatting.
Step 2:: Identify the box dimensions
- Width: $$\frac{1}{4} \, \text{ft}
From the image, the dimensions are: - Height: Not directly shown, but we can calculate it
Step 3:: Calculate the volume
V = l \times w \times h
The volume of a rectangular box is calculated by multiplying length × width × height.
Step 4:: Rearrange the given information
We know length = $$4 \frac{1}{2} \, \text{ft}$$ and width = $$\frac{1}{4} \, \text{ft}
We need to find the height that gives us 18 \, \text{ft}^{3}
Step 5:: Solve for height
18 = 4 \frac{1}{2} \times \frac{1}{4} \times h
Step 6:: Calculate height
h = \frac{18}{4 \frac{1}{2} \times \frac{1}{4}} = \frac{18}{1 \frac{1}{8}} = 16 \, \text{ft}
Final Answer
The volume of the box is 18 \, \text{ft}^{3} with dimensions 4 \frac{1}{2} \, \text{ft} \times \frac{1}{4} \, \text{ft} \times 16 \, \text{ft}.
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