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Step 1:I'll solve this step-by-step using the specified LaTeX formatting guidelines:
Step 2:: Convert fractions to a common denominator
\frac{7}{8}$$ is already in eighths
To compare fractions, we need to find a common denominator. The least common multiple of 4 and 8 is 8.
Step 3:: Compare the numerators
\frac{6}{8}$$ vs $$\frac{7}{8}
Now we can directly compare the numerators:
Step 4:: Determine the difference
7 - 6 = 1
So \frac{7}{8} is greater than \frac{3}{4} by \frac{1}{8}
Step 5:: Verify the difference
\frac{7}{8} - \frac{3}{4} = \frac{7}{8} - \frac{6}{8} = \frac{1}{8}
Final Answer
\frac{7}{8} is greater than \frac{3}{4} by \frac{1}{8}.
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