AP Calculus AB: 10.2.4 Regions Bound by Several Curves
This section explains how to find the area of regions bounded by more than two curves. It involves identifying points of intersection, breaking the integral into multiple parts based on which curves define the top and bottom, and always subtracting the lower function from the upper. Sketching the region helps ensure accuracy.
Regions Bound by Several Curves
Sometimes regions can be defined by more than two curves. When finding the area of a region bound by more than two curves, you must break the integral into different pieces wherever the curves bounding the region switch.
Key Terms
Regions Bound by Several Curves
Sometimes regions can be defined by more than two curves. When finding the area of a region bound by more than two curves, you must break the integ...
note
Regions can be defined in many different ways. Some regions are defined by several different curves. Always sketch the region you are worki...
Find the area of the shaded region bound by y = x^2, y = x + 4, y = −x + 6 and the y-axis.
19/3
What is the area of the region R bounded above by the curve y=2−x^2, and bounded below by the curves y=−x, and y=√x?
AR = 13/6
Find the area of the shaded region bound by y = (x − 1)^2 − 1, y = (x + 1)^2 − 1, and y = 3
18
Find the area of the region bound by the following curves:
y=√x, y=6−x, y=1.
13/6
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| Term | Definition |
|---|---|
Regions Bound by Several Curves | Sometimes regions can be defined by more than two curves. When finding the area of a region bound by more than two curves, you must break the integral into different pieces wherever the curves bounding the region switch. |
note |
|
Find the area of the shaded region bound by y = x^2, y = x + 4, y = −x + 6 and the y-axis. | 19/3 |
What is the area of the region R bounded above by the curve y=2−x^2, and bounded below by the curves y=−x, and y=√x? | AR = 13/6 |
Find the area of the shaded region bound by y = (x − 1)^2 − 1, y = (x + 1)^2 − 1, and y = 3 | 18 |
Find the area of the region bound by the following curves: y=√x, y=6−x, y=1. | 13/6 |