AP Calculus AB: 4.3.3 Combining Computational Techniques
This content explains the chain rule for differentiating composite functions and discusses how it integrates with other differentiation techniques like the product and quotient rules. It highlights the usefulness of different notations, especially Leibniz notation, for clarity and ease when applying the chain rule in complex problems involving multiple function combinations.
chain rule
The chain rule states that if f(x) = g(h(x)), where g and h are differentiable functions, then f is differentiable and
f’(x)=g’(h(x))*h’(x).
- Some functions are actually combinations of other functions, such as products or quotients. To differentiate these functions, it may be necessary to use several computational techniques and to use some more than once.
Key Terms
chain rule
The chain rule states that if f(x) = g(h(x)), where g and h are differentiable functions, then f is differentiable and
f’(x)=g’(h(x))*h’(x).
...
note
There are several ways to describe functions. Often
the y-notation is used instead of function notation.In function nota...
Find dy/dx: y=(2x+1)^2(3x)^2.
dy/dx=(2x+1)^2(18x)+(3x)^2(8x+4)
Find dy/dx, where y=(x+5)^3(x−3)^3
d/ydx=−24(x+5)^2 / (x−3)^4
A particle’s position is given by the function x(t)=(4−t)^3.What is the value of dx/dt when t=3?
dx/dt=−3
Given y=4x^3 / 3, find dy/dx.
dydx=4x^2
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| Term | Definition |
|---|---|
chain rule | The chain rule states that if f(x) = g(h(x)), where g and h are differentiable functions, then f is differentiable and |
note |
|
Find dy/dx: y=(2x+1)^2(3x)^2. | dy/dx=(2x+1)^2(18x)+(3x)^2(8x+4) |
Find dy/dx, where y=(x+5)^3(x−3)^3 | d/ydx=−24(x+5)^2 / (x−3)^4 |
A particle’s position is given by the function x(t)=(4−t)^3.What is the value of dx/dt when t=3? | dx/dt=−3 |
Given y=4x^3 / 3, find dy/dx. | dydx=4x^2 |
Find dy/dx given that y=3u^2,u=2v,and v=x/6. | dy/dx=2x/3 |
Given y=(3x^2+7x)^3, find dy/dx. | dy/dx=3(3x^2+7x)^2(6x+7) |
Given P=−3t^2+6t, find dP/dt. | dP/dt=−6t+6 |
If h=3k^2 and k=(3t)^2, then find dh/dt | dh/dt=972t^3 |
Given y=(x^2+3x)^3(2x^2−4x)^2,find dy/dx. | dy/dx=2(x2+3x)^3(2x^2−4x) (4x−4) + 3(2x^2−4x)^2(x^2+3x)^2(2x+3). |
Given y=2x^2, find dy/dx | dy/dx=4x |
Find dy/dx given that y=3u^2/3+2u^−1/2, and u=x^2. | dy/dx=4x^1/3−2x^−2 |
Given y=(2x+1)^2/ 3x^2, find dy/dx. | dy/dx=3x^2⋅4(2x+1)−(2x+1)^2⋅6x / (3x^2)^2 |