AP Calculus AB: 6.1.2 Finding the Derivative Implicitly
This flashcard set explores how to use implicit differentiation to find derivatives of equations not explicitly solved for one variable. It highlights the use of Leibniz notation and the chain rule to differentiate complex expressions involving both variables, and includes practical examples where the derivative depends on both π₯ and π¦.
Finding the Derivative Implicitly
Leibniz notation is another way of writing derivatives. This notation will be helpful when finding the derivatives of relations that are not functions.
Implicit differentiation uses the chain rule in a creative way to find the derivative of functions in implicit form.
Key Terms
Finding the Derivative Implicitly
Leibniz notation is another way of writing derivatives. This notation will be helpful when finding the derivatives of relations that are no...
note
Leibniz notation is another way of writing derivatives.
Notice that Leibniz notation can work like an operation,
instruct...
Given the equation cos^2x+cos^2y=cos^25Ο, find dy/dx.
dy/dx=βsin x cos x/sin y cos y
Given the equation
tan^2x^2βtan^2y^2=sec5βΟ,find dx/dy.
dx/dy=y tan y^2 sec^2 y^2/x tan x^2 sec^2 x^2
Given the equation x+y=0,find dy/dx.
dy/dx=β1
Given the equation s^2βt^2=16,find ds/dt.
ds/dt=t/s
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| Term | Definition |
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Finding the Derivative Implicitly |
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note |
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Given the equation cos^2x+cos^2y=cos^25Ο, find dy/dx. | dy/dx=βsin x cos x/sin y cos y |
Given the equation tan^2x^2βtan^2y^2=sec5βΟ,find dx/dy. | dx/dy=y tan y^2 sec^2 y^2/x tan x^2 sec^2 x^2 |
Given the equation x+y=0,find dy/dx. | dy/dx=β1 |
Given the equation s^2βt^2=16,find ds/dt. | ds/dt=t/s |
Given the equation 2x+4y=8,find dy/dx. | dy/dx=β1/2 |
Given the equation x^2+y^2=9,find dy/dx. | dy/dx=βx/y |
Given the equation 3x^2+4y^3=7,find dy/dx. | dy/dx=βx/2y^2 |
Suppose a curve is defined by the equation (x + y)^2 = 4. What is the equation of the line tangent to the curve at (3, β1)? | y = βx + 2 |
Given the equation xβ1βlny=8, find dy/dx. | dy/dx=βy/x^2 |
Given the equation x+3y=1,find dy/dx. | dy/dx=β1/3 |
Suppose a curve is defined by the equation 3xy+2(xy)^2+xy^3=1. Find dy/dx. | dy/dx=β3y+4xy^2+y^3/3x+4x^2y+3xy^2 |
Given the equation sinx^2+siny^2=5,find dy/dx. | dy/dx=βxcosx^2/ycosy^2 |