AP Calculus AB: 7.1.1 Acceleration and the Derivative
This set of flashcards explains the relationship between position, velocity, and acceleration through derivatives. It highlights how tangent lines and derivatives help approximate function values, find roots, and optimize outputs. The cards also include practical examples such as calculating acceleration from velocity functions.
Acceleration and the Derivative
Velocity is the rate of change of position. Acceleration is the rate of change of velocity.
Tangent lines can be used to approximate functions that are difficult to evaluate. The slopes of tangent lines can be used to optimize outputs such as profits and
areas.
Key Terms
Acceleration and the Derivative
Velocity is the rate of change of position. Acceleration is the rate of change of velocity.
Tangent lines can be used to app...
note
Velocity is the rate of change of position.
Acceleration is the rate of change of velocity. So
the velocity function is t...
Suppose an object falling out of an airplane has a velocity of v (t) = −32t + 64 where t is in seconds and v is in feet per second. What is the acceleration of the object when t = 1?
−32 ft/sec2
Given that a particular moving object’s velocity is given by the equation v(t)=−32t+110, what is the equation for the object’s acceleration?
a (t) = −32
Given that a particular moving object’s velocity is given by the equation v(t)=65t−2t^2, what is the equation for the object’s acceleration?
a (t) = 65 − 4t`
Given that a particular moving object’s velocity is given by the equation v(t)=65−3t, what is the equation for the object’s acceleration?
a (t) = −3
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| Term | Definition |
|---|---|
Acceleration and the Derivative |
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note |
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Suppose an object falling out of an airplane has a velocity of v (t) = −32t + 64 where t is in seconds and v is in feet per second. What is the acceleration of the object when t = 1? | −32 ft/sec2 |
Given that a particular moving object’s velocity is given by the equation v(t)=−32t+110, what is the equation for the object’s acceleration? | a (t) = −32 |
Given that a particular moving object’s velocity is given by the equation v(t)=65t−2t^2, what is the equation for the object’s acceleration? | a (t) = 65 − 4t` |
Given that a particular moving object’s velocity is given by the equation v(t)=65−3t, what is the equation for the object’s acceleration? | a (t) = −3 |
Which of the following statements about acceleration is true? | Acceleration is the rate of change in velocity. |
A car is moving at a constant acceleration of 3 m / sec2. If the car is moving with a velocity of 20 m / sec at t = 0, how fast is the car moving when t = 3? | 29 m / sec |
A jogger is moving at a constant velocity of 8 ft / sec. How far has the jogger moved after 20 seconds? | 160 feet |