AP Calculus AB: 9.5.3 Trigonometric Substitution Involving a Definite Integral: Part Two
This section builds on the previous part by demonstrating how to complete definite integrals using trigonometric substitution. It emphasizes converting back to the original variable using inverse trig functions before evaluating at the limits and highlights the role of the reference triangle in guiding substitutions.
Trigonometric Substitution Involving a Definite Integral: Part Two
When computing a definite integral using substitution, first ignore the limits of integration and treat the integral like an indefinite integral. Convert back to the original variable before evaluating at the endpoints.
The labeled right triangle serves as a dictionary for making trig substitutions.
Key Terms
Trigonometric Substitution Involving a Definite Integral: Part Two
When computing a definite integral using substitution, first ignore the limits of integration and treat the integral like an indefinite int...
note
In the previous lecture you used a trigonometric substitution to evaluate the indefinite integral corresponding to this definite integral. ...
Evaluate ∫1 0 x/√4x−x^2dx
2π/3−√3
Evaluate ∫√3 1 dx/x√x^2+3.
1/√3 ln √2−1 / b2−√3
Evaluate ∫ 4 2 √x^2−4 / x dx
2√3−2π/3
Evaluate ∫0 −1 dx/(5−4x−x^2)^3/2
1/9(2√5/5−√2/4)
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| Term | Definition |
|---|---|
Trigonometric Substitution Involving a Definite Integral: Part Two |
|
note |
|
| 2π/3−√3 |
Evaluate ∫√3 1 dx/x√x^2+3. | 1/√3 ln √2−1 / b2−√3 |
Evaluate ∫ 4 2 √x^2−4 / x dx | 2√3−2π/3 |
Evaluate ∫0 −1 dx/(5−4x−x^2)^3/2 | 1/9(2√5/5−√2/4) |
Evaluate ∫ 5 4 1/x^2√25−x^2 dx. | 3/100 |
Evaluate ∫1 2/3 √9x^2−4/x dx. | √5−2sec^−1 3/2 |
Evaluate ∫1 0 dx/(x^2+2x+2)^2 | 1/2(tan^−1 2− π/4 −1/10) |