Precalc Final Answers

Mathematics36 CardsCreated 4 months ago

This deck contains 36 flashcards covering solutions to various precalculus problems, including trigonometric identities, vector operations, and complex numbers.

Find csc x and cot x if cos x = -4/7 and sin x > 0

csc x = (7 √(33))/33 cot x = (-4 √33)/33
Tap or swipe ↕ to flip
Swipe ←→Navigate
1/36

Key Terms

Term
Definition
Find csc x and cot x if cos x = -4/7 and sin x > 0
csc x = (7 √(33))/33 cot x = (-4 √33)/33
When tan x =4/3 where π ≤ x ≤ 3 π/2, Find cos 2x.
-7/25
When cos x = -8/17 where π≤x≤3π/2, find cos 2x.
-161/289
Solve this eqution for 0≤x≤2π (√2)sin(x)csc(x) + 2csc(x) = 2sin(x) + 2csc(x)
x= π/4, 3π/4
Solve: cos^2(x) + 2 = 2cos(x) + 1
x = 0, 2π
0=2 tan(x) - sec^2 (x)
x = π/4 , 5π/4

Related Flashcard Decks

Study Tips

  • Press F to enter focus mode for distraction-free studying
  • Review cards regularly to improve retention
  • Try to recall the answer before flipping the card
  • Share this deck with friends to study together
TermDefinition
Find csc x and cot x if cos x = -4/7 and sin x > 0
csc x = (7 √(33))/33 cot x = (-4 √33)/33
When tan x =4/3 where π ≤ x ≤ 3 π/2, Find cos 2x.
-7/25
When cos x = -8/17 where π≤x≤3π/2, find cos 2x.
-161/289
Solve this eqution for 0≤x≤2π (√2)sin(x)csc(x) + 2csc(x) = 2sin(x) + 2csc(x)
x= π/4, 3π/4
Solve: cos^2(x) + 2 = 2cos(x) + 1
x = 0, 2π
0=2 tan(x) - sec^2 (x)
x = π/4 , 5π/4
-csc^2 (x) +2 = 0
x = π/4 , 3π/4, 5π/4, 7π/4
cos(x) = cos 2(x)
x = 0, 2π/3, 4π/3
5 + sin x = (10 + √3)/2
x = π/3, 2π/3
arctan (tan 3π/4) = x
x = -π/4
arctan (sec(π)) = x
x = -π/4
arccos (sin(0)) = x
x = π/2
arcsin (csc (π/2)) = x
x = π/2
Solve the triangle: c = 17 cm, a = 15 cm, b = 28 cm
angle A = 27.03 degrees angle B = 121.96 degrees angle C = 31.101 degrees
Solve the triangle: angle C = 65 degrees, b = 35 yd, c = 32 yd
angle B = 82.43 degrees angle A = 32.57 degrees a = 19.01 yd
Solve the triangle: angle C = 62 degrees, b = 15 mi, c = 10 mi, SSA
NO TRIANGLE
cos ( -7π/12)
(√2 - √6)/4
tan (5π/12)
2 + √3

u = <4,1>
v = <2,-1>
Find: - u - v
Component Form:
Magnitude:
Direction Angle:

Component Form: <-6,0> or -6i
Magnitude: 6
Direction Angle: 180 degrees

u = <4,6>
g = <-12,4>
Find: u + g
Component Form:
Magnitude:
Direction Angle:

Component Form: <-8,10>
Magnitude: 2√41
Direction Angle: 128.66 degrees

Find the angle between the two vectors: u = -6i - 3j v = 2i - 8j
x = 77.47 degrees
Find the angle between the two vectors: u = <7,2> v = <-6,-5>
x = 156.14 degrees
Write the vector in component form: Vector CD where C = <0,-2> D= <1,0>
<1,2>
Find the component form of the resultant vector: a = <9,-40> Find 2a
<18,-80> or 18i-80j
Find the direction angle for AB where; A = <0,-5> B = <1,5>
<1,10> is the vector so the direction angle is 84.29 degrees.
Find the dot product: u = <5,-4> v = <-3,-5>
5
Find the dot product: u = - 8i - 5j v = 7i - 4j
-36
State if the vector is parallel, orthogonal, or neither: u = <40,-40> v = <-6,8>
neither
State if the vector is parallel, orthogonal, or neither: u = <-12,-10> v = <5,-6>
orthogonal
Write in trig form: -√3 + i
= 2(cos (-π/6) + i sin (-π/6)) or = 2(cos 150 + i sin 150)
Write in trig form: √6 - 3i√2
= 2√6 (cos 300 + i sin 300) or = 2√6 (cos π/3 + i sin π/3)
Write in rectangular form: 4(cos 60 + i sin 60)
2 + 2i√3
Write in rectangular form: 4(cos (4π/3) + i sin (4π/3) )
- 2 - 2i√3
√6(cos 90 + i sin 90) x 4 (cos 120 + i sin 120)
-6√2 - 2√6 i
√31 (cos 240 + isin 240)/ √31 (cos 210 + i sin 210)
√3/2 + i/2
[(3√3)/2 + 3i/2)] ^3
27i