Q
QuestionPhysics

An 80.0 kg man is standing on a frictionless ice surface when he throws a 2.00 kg book at 10.0 m/s. With what velocity does the man move across the ice?
6 months agoReport content

Answer

Full Solution Locked

Sign in to view the complete step-by-step solution and unlock all study resources.

Step 1
: Write down the principle of conservation of momentum.

The total momentum of a closed system remains constant before and after an interaction, assuming no external forces act on the system. In this case, the man and the book form a closed system.

Step 2
: Express the principle of conservation of momentum mathematically.

m_{man} v_{man,i} + m_{book} v_{book,i} = m_{man} v_{man,f} + m_{book} v_{book,f}
Let m\_man be the mass of the man, m\_book be the mass of the book, v\_man,i be the initial velocity of the man, v\_book,i be the initial velocity of the book, v\_man,f be the final velocity of the man, and v\_book,f be the final velocity of the book. Then, the principle of conservation of momentum can be written as:

Final Answer

The man moves across the ice with a velocity of 0.25 m/s.