QQuestionPhysics
QuestionPhysics
The density of glycerin is 1.26 grams/cm³. How many pounds/ft³ is this? Use the conversion rates of 454 grams/pound and 28,317 cm³/ft³. Express your answer to the correct number of significant figures.
The density is ___ pounds/ft³.
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Answer
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Step 1: Convert the given density of glycerin from grams/cm³ to pounds/cm³.
1.26 frac{g}{cm^3} times frac{1 pound}{454 g} = 0.002774713... frac{pound}{cm^3}
First, we need to convert the given density from grams to pounds. Using the conversion factor 454 grams/pound, we get:
Step 2: Convert the density from pounds/cm³ to pounds/ft³.
0.002774713... frac{pound}{cm^3} times (28,317 frac{cm^3}{ft^3})^2 = 2.411376... frac{pounds}{ft^3}
Now, we need to convert the density from pounds/cm³ to pounds/ft³ using the conversion factor 28,317 cm³/ft³:
Final Answer
The density of glycerin is approximately 2.41 pounds/ft³.
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