QQuestionBiochemistry
QuestionBiochemistry
The molecular weight of Potassium chloride (KCl) is 74.55 g/mol. How many grams would you need for 650 ml of a 35 mM solution?
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Answer
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Identify the given information
- Desired concentration: $$35 \text{ mM} = 0.035 \frac{\text{mol}}{\text{L}}
- Volume of solution: 650 \text{ ml}
Step 3:: Convert volume to liters
650 \text{ ml} \times \frac{1 \text{ L}}{1000 \text{ ml}} = 0.650 \text{ L}
Step 4:: Calculate moles of KCl needed
\text{Moles} = (0.035 \frac{\text{mol}}{\text{L}}) \times (0.650 \text{ L}) = 0.02275 \text{ mol}
- Moles = Concentration × Volume
Step 5:: Calculate mass of KCl
\text{Mass} = (0.02275 \text{ mol}) \times (74.55 \frac{g}{\text{mol}}) = 1.695 \text{ g}
- Mass = Moles × Molecular Weight
Final Answer
1.70 \text{ g of KCl} (rounded to two decimal places)
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