Optimization Of Shipping Capacity For Refrigerators And TVs On An 18-Wheeler

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Optimization of Shipping Capacity for Refrigerators and TVs on an 18 - Wheeler Shipping restrictions. The accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18 - wheeler. a) Write an inequality to describe this region. The line passing through (0, 330) and (110, 0) is: m = (0 – 330)/(110 – 0) = - 3 y = mx + c y = - 3x + c 0 = - 3(110) + c => c = 330 So the line is y = - 3x +330 or y + 3x = 330 Since the region is under the line so the inequality describing the region is y + 3x < 330 b) Will the truck hold 71 refrigerators and 118 TVs? No, because the point (118, 71) does not lie in the region or it does not satisfy the inequality as 71 + 3(118) < 330 425 < 330 is not true. c) Will the truck hold 51 refrigerators and 176 TVs? Yes. because the point (51, 176) lies in the region or it satisfies the inequality as 176 + 3(51) < 330 327 < 330 is true.
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