QQuestionChemistry
QuestionChemistry
Aluminum has ___ valence electrons. The easiest way for Al to acquire a full outer shell is to __ __ electrons, forming an ion with a ___ charge.
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Determine the electron configuration of Aluminum
- Its electron configuration is $$1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{1}
- Aluminum's atomic number is 13
Step 3:: Count valence electrons
- Valence electron count: $$2 + 1 = 3$$ valence electrons
- Valence electrons are in the outermost shell - For Aluminum, these are the electrons in the 3s and 3p orbitals
Step 4:: Determine how Aluminum achieves a full outer shell
- By losing $$3$$ electrons, it forms a $$3^{+}$$ ion
- A full outer shell requires 8 electrons
Final Answer
- Aluminum has 3 valence electrons - The easiest way for Al to acquire a full outer shell is to lose 3 electrons, forming an ion with a 3^{+} charge
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