QQuestionChemistry
QuestionChemistry
Atomic number of aluminum is 13 and mass number is 27.
Calculate the number of electrons, protons, and neutrons in its atom.
Represent the ion of this element.
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Answer
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Step 1:
\text{Number of protons} = 13
First, let's find the number of protons in an aluminum atom. The atomic number of aluminum is 13, which means there are 13 protons in the nucleus of an aluminum atom.
Step 2:
\text{Number of electrons} = 13
Since an atom is electrically neutral, the number of electrons in a neutral aluminum atom is equal to the number of protons. Therefore, there are also 13 electrons in a neutral aluminum atom.
Step 3:
\text{Number of neutrons} = \text{Mass number} - \text{Number of protons} = 27 - 13 = 14
To calculate the number of neutrons, we need to subtract the number of protons from the mass number. The mass number of aluminum is 27, so there are: neutrons in a neutral aluminum atom.
Step 4:
\text{Aluminum ion (Al³⁺):} \quad \boxed{ extrm{Al}^{3+}}
Now, let's represent the ion of this element. Aluminum can lose three electrons to form a + 3 ion, called the aluminum ion (Al³⁺). The charge of the ion is represented as a superscript on the top right corner of the chemical symbol.
Final Answer
- Number of protons: 13 - Number of electrons (in a neutral atom): 13 - Number of neutrons: 14 - Aluminum ion (Al³⁺) representation: $\boxed{ extrm{Al}^{3 +}}$
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