QQuestionChemistry
QuestionChemistry
Calculate the molar mass of magnesium sulfate heptahydrate, MgSO^4 ⋅7H^2O.
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Answer
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Identify the chemical formula
The chemical formula is $$\mathrm{MgSO_{4} \cdot 7H_{2}O}$$, which means we need to calculate the molar mass of magnesium sulfate with 7 water molecules.
Step 3:: Determine the atomic masses of each element
- Hydrogen (H): $$m_{\mathrm{H}} = 1.008 \mathrm{~g/mol}
- Sulfur (S): m_{\mathrm{S}} = 32.065 \mathrm{~g/mol}
Step 4:: Calculate the molar mass of the anhydrous magnesium sulfate (MgSO4)
24.305 + 32.065 + (4 \times 16.00) = 24.305 + 32.065 + 64.00 = 120.370 \mathrm{~g/mol}
- S: 1 \times 32.065 \mathrm{~g/mol} Subtotal for MgSO^4:
Step 5:: Calculate the molar mass of the water molecules (7H^2O)
14 \times 1.008 + 7 \times 16.00 = 14.112 + 112.00 = 126.112 \mathrm{~g/mol}
- O: 7 \times 16.00 \mathrm{~g/mol} Subtotal for water:
Step 6:: Sum the molar masses
120.370 + 126.112 = 246.482 \mathrm{~g/mol}
Total molar mass = MgSO^4 + 7H^2O
Final Answer
The molar mass of magnesium sulfate heptahydrate (\mathrm{MgSO_{4} \cdot 7H_{2}O}) is 246.482 \mathrm{~g/mol}.
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