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QuestionChemistry

Calculate the molar mass of the compound containing Ag+ and SO^42− ions.
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Step 1:
I'll solve this problem step by step, following the specified LaTeX formatting guidelines:

Step 2:
: Identify the ions in the compound

The compound contains silver (Ag+) and sulfate (SO4^{2 -}) ions. This suggests we're dealing with silver sulfate (Ag^2SO4).

Step 3:
: Determine the number of atoms of each element

- Silver (Ag): 2 atoms - Sulfur (S): 1 atom - Oxygen (O): 4 atoms

Step 4:
: Look up the atomic masses

- Oxygen (O): $$m_{O} = 16.00 \mathrm{~g/mol}
- Sulfur (S): m_{S} = 32.07 \mathrm{~g/mol}

Step 5:
: Calculate the molar mass by summing the masses of all atoms

\begin{align}
\text{Molar Mass} &= (2 \times m_{Ag}) + (1 \times m_{S}) + (4 \times m_{O}) \ &= (2 \times 107.87) + (1 \times 32.07) + (4 \times 16.00) \ &= 215.74 + 32.07 + 64.00 \ &= 311.81 \mathrm{~g/mol} \end{align}

Final Answer

The molar mass of Ag^2SO^4 is 311.81 \mathrm{~g/mol}.