QQuestionChemistry
QuestionChemistry
Calculate the number of oxygen atoms in a 110.0 g sample of forsterite (Mg^2 SiO 4 ).
Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
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Answer
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Step 1:: Find the molar mass of forsterite (Mg^2 SiO4)
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Step 2:: Calculate the number of moles in the sample
To find the number of moles (n) in 110.0 g of forsterite, divide the mass of the sample by its molar mass.
Step 3:: Determine the number of oxygen atoms in one mole of forsterite
Forsterite contains four oxygen atoms per molecule. Therefore, there are 4 mol of oxygen atoms in 1 mol of forsterite.
Step 4:: Find the number of oxygen atoms in the sample
To find the number of oxygen atoms in the sample, multiply the number of moles of forsterite by the number of oxygen atoms per mole of forsterite. \text{Number of O atoms} = n_{\text{forsterite}} \times \text{O atoms per mole of forsterite} \begin{align*} &= 0.667~\text{mol} \times 4~\text{mol O atoms} \ &= 2.668~\text{mol O atoms} \end{align*}
Step 5:: Convert moles to grams
To report the number of oxygen atoms in the sample with the correct units, multiply the number of moles of oxygen atoms by the molar mass of oxygen (15.9994 g/mol). \text{Mass of O atoms} = \text{Number of O atoms} \times \text{Molar mass of O} \begin{align*} &= 2.668~\text{mol} \times 15.9994~\text{g/mol} \ &= 42.60~\text{g} \end{align*}
Final Answer
The number of oxygen atoms in a 110.0 g sample of forsterite is approximately 2.668 mol (42.60 g).
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