QQuestionChemistry
QuestionChemistry
Choose the correct Lewis dot symbol for the $S^{2 -}$ ion:
A)
S^{--}:: \text {. }
B)
S^{--}::^{2 -}
C)
S^{2 -}
D)
-S^{--}--{ }^{2 -}
E)
S^{--}: \text {. }
12 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1:Let's solve this step by step:
Step 2:: Understand the Lewis dot symbol requirements
- The $S^{2-}$ ion has gained 2 electrons, so it will have 8 total valence electrons
- A Lewis dot symbol represents the valence electrons of an atom or ion - Sulfur is in Group 16 (VIA), so it has 6 valence electrons in its neutral state
Step 3:: Analyze the Lewis dot symbol structure
- The central atom (S) should be in the center - The 8 valence electrons should be distributed around the S atom - Electrons are typically placed in pairs on each side of the atom
Step 4:: Evaluate the given options
- Option E: $$S^{--}: \text{.}$$ - Incorrect number of electrons
- Option B: S^{--}::^{2 -} - Incorrect representation
Step 5:: Correct Lewis dot symbol
- The correct Lewis dot symbol should show 8 electrons (4 pairs) around the S atom - None of the given options match this requirement
Final Answer
The correct representation would show 8 valence electrons (4 electron pairs) distributed around the sulfur atom.
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students