QQuestionChemistry
QuestionChemistry
Choose the correct Lewis electron-dot diagram for an atom of boron.
| 1. | $\cdot \mathrm{B}^{\cdot}$ |
| --- | --- |
| 2. | $\mathrm{B}^{\cdot}$ |
| 3. | $: \mathrm{B}:$ |
| 4. | $: \mathrm{B}^{\cdot}$ |
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Answer
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Step 1:: Identify the correct Lewis electron-dot diagram for boron.
Boron is in the third period of the periodic table and has atomic number 5. This means that a neutral boron atom has 5 electrons: 2 in the first energy level and 3 in the second energy level. The Lewis electron-dot diagram for a neutral boron atom should represent this electron configuration.
Step 2:: Examine the given options.
Let's analyze the four given options:
Step 3:$\cdot \mathrm{B}^{\cdot}$ : This option shows a boron atom with one electron and one positive charge, which means it has 3 electrons.
This is not the correct electron configuration for a neutral boron atom.
Step 4:$\mathrm{B}^{\cdot}$ : This option shows a boron atom with one positive charge, which means it has 4 electrons.
This is also not the correct electron configuration for a neutral boron atom.
Step 5:$: \mathrm{B}:$ : This option shows a boron atom with 4 electrons, which is one electron short of the correct electron configuration.
Step 6:$: \mathrm{B}^{\cdot}$ : This option shows a boron atom with 3 electrons and one negative charge.
This is not the correct electron configuration for a neutral boron atom.
Step 7:: Select the correct option.
The correct Lewis electron-dot diagram for a neutral boron atom should have 2 electrons in the first energy level and 3 electrons in the second energy level, with a total of 5 electrons. Therefore, the correct option is: :\mathrm{B}:
Final Answer
The correct Lewis electron-dot diagram for an atom of boron is $: \mathrm{B}:$. This diagram represents a neutral boron atom with 5 electrons, 2 in the first energy level and 3 in the second energy level.
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