QQuestionChemistry
QuestionChemistry
Determine the electron geometry (eg) and molecular geometry (mg) of BrF^3.
A. eg = trigonal planar, mg = trigonal planar
B. eg = trigonal bipyramidal, mg = T-shape
C. eg = trigonal planar, mg = bent
D. eg = trigonal bipyramidal, mg = see-saw
E. eg = tetrahedral, mg = trigonal pyramidal
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Answer
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Step 1:Let's solve this step by step using VSEPR theory:
Step 2:: Determine the number of electron domains around the central atom
• Bromine (Br) is the central atom • Count the number of electron domains: - 3 fluorine bonds: 3 bonding domains - 2 lone pairs on bromine: 2 non-bonding domains • Total electron domains = 5
Step 3:: Electron Geometry Determination
• Electron geometry is $$trigonal bipyramidal
• 5 total electron domains • This matches the description in options B and D
Step 4:: Molecular Geometry Determination
• This results in a $$T-shape$$ molecular geometry
• 3 bonding domains • 2 lone pairs • Lone pairs occupy equatorial positions to minimize repulsion
Step 5:: Verify the Correct Option
• Electron geometry: $$trigonal bipyramidal
• Molecular geometry: T-shape
Final Answer
• Electron Geometry (eg) = trigonal bipyramidal • Molecular Geometry (mg) = T-shape
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