QQuestionChemistry
QuestionChemistry
Determine the electron geometry (EG) and molecular geometry (MG) of NCl^3.
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Determine the central atom and draw the Lewis structure
* Total valence electrons: $$5 + 21 = 26$$ electrons
- The central atom is nitrogen (N) - Count the valence electrons: * N: 5 valence electrons * Cl: 7 valence electrons × 3 = 21 valence electrons
Step 3:: Arrange the atoms in the Lewis structure
- N is the central atom - Three Cl atoms are bonded to N - Remaining electrons form lone pairs
Step 4:: Count electron domains around the central atom
- Total electron domains: $$4$$ domains
- 3 single bonds to Cl atoms - 1 lone pair on the central N atom
Step 5:: Determine Electron Geometry (EG)
- Electron Geometry: $$\text{Tetrahedral}
- With 4 total electron domains, the electron geometry follows the tetrahedral arrangement
Step 6:: Determine Molecular Geometry (MG)
- Molecular Geometry: $$\text{Trigonal Pyramidal}
- 3 bonding domains - 1 lone pair - This creates a trigonal pyramidal molecular geometry
Final Answer
- Electron Geometry (EG): \text{Tetrahedral} - Molecular Geometry (MG): \text{Trigonal Pyramidal}
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