QQuestionChemistry
QuestionChemistry
Determine the molecular geometry and bond angles for borane, BH
3
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Step 1:I'll solve this problem step by step, following the LaTeX formatting guidelines precisely:
Step 2:: Determine the Lewis Structure
- Total valence electrons: $$3 + (3 \times 1) = 6$$ electrons
- Borane (BH₃) is a molecule composed of one boron (B) atom and three hydrogen (H) atoms - Boron has 3 valence electrons - Each hydrogen contributes 1 electron
Step 3:: Electron Arrangement
- Boron is the central atom - Arrange 6 electrons to form single bonds between B and H \begin{array}{c} H-B-H \ H \end{array}
Step 4:: Determine Electron Geometry
- Use Valence Shell Electron Pair Repulsion (VSEPR) theory - Total electron domains: 3 - No lone pairs on central boron atom - Electron geometry is trigonal planar
Step 5:: Molecular Geometry
- All electron domains are bonding domains - Molecular geometry matches electron geometry - Molecular geometry is trigonal planar
Step 6:: Bond Angles
- In a trigonal planar geometry, bond angles are $$120^{\circ}
- Each H-B-H angle is 120^{\circ}
Final Answer
- Molecular Geometry: Trigonal Planar - Bond Angles: 120^{\circ}
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