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Step 1:I'll solve this problem step by step, following the specified LaTeX and formatting guidelines:
Step 2:: Determine the total number of valence electrons
- Total valence electrons: $$8 + 6 + 6 = 20$$ electrons
- Carbon (C): 4 valence electrons × 2 = 8 electrons - Oxygen (O): 6 valence electrons × 1 = 6 electrons - Hydrogen (H): 1 valence electron × 6 = 6 electrons
Step 3:: Arrange the atoms
- Structural skeleton: $$H_3C-O-CH_3
- Place the oxygen atom in the center, connecting the two carbon atoms
Step 4:: Connect atoms with single bonds
- Bonds used so far: $$6 \times 2 = 12$$ electrons
- First, connect each carbon to the oxygen with a single bond - Connect hydrogens to carbons
Step 5:: Add remaining electrons as lone pairs
- Remaining electrons: $$20 - 12 = 8$$ electrons
- Place these as lone pairs on the oxygen atom - Oxygen typically has two lone pairs
Step 6:: Check octet rule
- Each carbon has 4 electrons (single bonds) - Oxygen has 4 electrons in bonds and 4 electrons in lone pairs - All atoms satisfy the octet rule Final Lewis Structure: \begin{array}{c} H_3 C-O-CH_3 \ \text{with two lone pairs on oxygen} \end{array}
Final Answer
- Each carbon has 4 electrons (single bonds) - Oxygen has 4 electrons in bonds and 4 electrons in lone pairs - All atoms satisfy the octet rule Final Lewis Structure: \begin{array}{c} H_3 C-O-CH_3 \ \text{with two lone pairs on oxygen} \end{array}
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