QQuestionChemistry
QuestionChemistry
Draw Lewis structures for each molecular formula:
a. C₂H₄Cl₂ (two isomers)
b. C₃H₈O (three isomers)
c. C₃H₆ (two isomers)
12 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1:I'll solve this problem step by step, focusing on drawing Lewis structures for the given molecular formulas.
a. C₂H₄Cl₂ (two isomers)
Step 2:: Determine the total number of valence electrons
- Total valence electrons: $$8 + 4 + 14 = 26$$ electrons
- Carbon (C): 4 valence electrons × 2 = 8 - Hydrogen (H): 1 valence electron × 4 = 4 - Chlorine (Cl): 7 valence electrons × 2 = 14
Step 3:: Isomer 1 - 1,1 -Dichloroethane
- Central carbon atoms connected - Two chlorine atoms attached to one carbon - Hydrogen atoms fill remaining valence positions Lewis structure: \begin{array}{c} H-C(Cl)_{2}-C-H_{2} \end{array}
Step 4:: Isomer 2 - 1,2 -Dichloroethane
- Carbon atoms connected - One chlorine atom on each carbon - Hydrogen atoms fill remaining valence positions Lewis structure: \begin{array}{c} H-C(Cl)-C(Cl)-H_{2} \end{array} b. C₃H₈O (three isomers)
Step 5:: Determine total valence electrons
- Total valence electrons: $$12 + 8 + 6 = 26$$ electrons
- Carbon (C): 4 valence electrons × 3 = 12 - Hydrogen (H): 1 valence electron × 8 = 8 - Oxygen (O): 6 valence electrons × 1 = 6
Step 6:: Isomer 1 - Propan- 1 -ol
- Oxygen at end of carbon chain - Hydroxyl group (-OH) attached to first carbon Lewis structure: \begin{array}{c} H-C-C-C-O-H \end{array}
Step 7:: Isomer 2 - Propan- 2 -ol
- Oxygen attached to middle carbon - Hydroxyl group (-OH) on second carbon Lewis structure: \begin{array}{c} H-C-C(O-H)-C-H_{3} \end{array}
Step 8:: Isomer 3 - Methoxyethane
- Oxygen as connecting group between carbons - Methoxy group (-O-CH₃) Lewis structure: \begin{array}{c} H-C-O-C-H_{3} \end{array} c. C₃H₆ (two isomers)
Step 9:: Determine total valence electrons
- Total valence electrons: $$12 + 6 = 18$$ electrons
- Carbon (C): 4 valence electrons × 3 = 12 - Hydrogen (H): 1 valence electron × 6 = 6
Step 10:: Isomer 1 - Propene
- Double bond between two carbon atoms - Hydrogen atoms fill remaining positions Lewis structure: \begin{array}{c} H_{2}C=CH-CH_{3} \end{array}
Step 11:: Isomer 2 - Cyclopropane
- Three-carbon ring structure - Single bonds between carbons - Hydrogen atoms fill remaining positions Lewis structure: \begin{array}{c} \text{Triangular ring with hydrogen atoms attached} \end{array}
Final Answer
- C₂H₄Cl₂: Two isomers (1,1 -dichloroethane and 1,2 -dichloroethane) - C₃H₈O: Three isomers (propan- 1 -ol, propan- 2 -ol, methoxyethane) - C₃H₆: Two isomers (propene and cyclopropane)
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students