QQuestionChemistry
QuestionChemistry
Draw the Lewis dot structure for Mg^2 +. Show the charge. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom.
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Answer
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Step 1:: Understand the problem
We need to draw the Lewis dot structure for the Mg^2 + ion and show the charge.
Step 2:: Determine the number of valence electrons
Mg is in the 2nd period of the periodic table, so it has 2 valence electrons. However, we are dealing with the Mg^2 + ion, which has lost 2 electrons and has a charge of + 2. Therefore, the Mg^2 + ion has no valence electrons.
Step 3:: Place the nucleus and core electrons
Start by drawing the magnesium nucleus with the charge of + 2, as there are 2 fewer electrons than in a neutral magnesium atom. Since Mg^2 + has no valence electrons, there are no core electrons to draw around the nucleus.
Step 4:: Distribute the remaining valence electrons
Since Mg^2 + has no valence electrons, there are no electrons to distribute.
Step 5:: Satisfy the octet rule for the central atom
The octet rule is not applicable here, as there are no valence electrons around the magnesium nucleus.
Step 6:: Add remaining electrons to complete octets
There are no remaining electrons to add.
Step 7:: Draw the Lewis structure
Draw the magnesium nucleus with a charge of + 2, and leave it with no electrons around it.
Final Answer
The Lewis dot structure for Mg^2 + is simply a magnesium nucleus with a charge of + 2 and no electrons around it.
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