Answer
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Step 1:: Determine the total number of valence electrons in the HBr molecule.
Hydrogen (H) is in the 1st period of the periodic table and has 1 valence electron. Bromine (Br) is in the 4th period and has 7 valence electrons, as it is in the same group as other halogens. Therefore, the HBr molecule has a total of 1 + 7 = 8 valence electrons.
Step 2:: Draw the skeletal structure of HBr.
Since HBr is a diatomic molecule, its skeletal structure consists of two atoms, hydrogen (H) and bromine (Br), connected by a single bond.
Step 3:: Place the remaining valence electrons as lone pairs on the atoms.
Hydrogen has no lone pairs, as it only needs one electron to complete its octet. Bromine, however, needs three more electrons to complete its octet. Place two lone pairs on bromine to satisfy this requirement.
Step 4:: Draw the Lewis dot structure of HBr.
H - Br | | | | - - In the Lewis dot structure above, the line represents the single covalent bond between hydrogen and bromine, and each dot represents a valence electron. The bromine atom has two lone pairs of electrons, while the hydrogen atom has none.
Final Answer
The Lewis dot structure of HBr is shown above, with hydrogen and bromine connected by a single bond, and bromine having two lone pairs of electrons.
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