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Step 1:I'll solve this Lewis structure problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Determine the total number of valence electrons
Total valence electrons: $$6 + (7 \times 5) + 1 = 6 + 35 + 1 = 42$$ electrons
- Fluorine (F): 7 valence electrons × 5 fluorines
Step 3:: Arrange central atom and surrounding atoms
- Selenium will be the central atom - Five fluorine atoms will be arranged around selenium
Step 4:: Connect atoms with single bonds
Remaining electrons: $$42 - 10 = 32$$ electrons
- Draw single bonds between selenium and each fluorine
Step 5:: Add lone pairs
- Place $$2$$ lone pairs on selenium
- Place 6 lone pairs on each fluorine atom (30 electrons)
Step 6:: Check octet rule and formal charges
- Each fluorine has $$8$$ electrons
- Selenium has expanded octet (more than 8 electrons) - Formal charge calculation confirms stable structure
Final Answer
The Lewis structure for [SeF_{5}]^{-} will have: - Selenium at center - Five fluorine atoms bonded to selenium - Each fluorine with 6 lone pair electrons - 2 lone pairs on selenium - Single bonds between selenium and fluorines
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