QQuestionChemistry
QuestionChemistry
Draw the Lewis structure for SiO^2 and indicate how many unshared pairs of electrons are present on the silicon.
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Step 1:I'll solve this step by step, following the LaTeX formatting guidelines precisely:
Step 2:: Determine the total number of valence electrons
\text{Total valence electrons} = 4 + (2 \times 6) = 16
- Silicon (Si): 4 valence electrons - Oxygen (O): 6 valence electrons - Two oxygen atoms are present
Step 3:: Arrange atoms and form single bonds
\text{Remaining electrons after bonding} = 16 - 4 = 12
- Silicon will be the central atom - Connect both oxygen atoms to silicon
Step 4:: Distribute remaining electrons as lone pairs
\text{Remaining electrons} = 12 - 6 = 6
- Place remaining electrons around oxygen atoms first - Each oxygen atom will have 3 lone pairs
Step 5:: Complete the Lewis structure
- The remaining 6 electrons cannot be placed on silicon - Silicon will have 0 unshared electron pairs - Oxygen atoms will have 3 lone pairs each
Final Answer
The Lewis structure for SiO^2 has 0 unshared pairs of electrons on the silicon atom.
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